JEE Main 20268 Apr, Evening shiftMathematicsEasyMatrices and Determinants245× since 2002If the system of linear equations: x+y+z=6x+y+z=6x+y+z=6, x+2y+5z=10x+2y+5z=10x+2y+5z=10, 2x+3y+λz=μ2x+3y+\lambda z=\mu2x+3y+λz=μ has infinitely many solutions, then the value of λ+μ\lambda+\muλ+μ equals :AOption A. 12BOption B. 16COption C. 22DOption D. 28CheckSkip · show solution