JEE Main 202431 Jan, Morning shiftMathematicsMediumMatrices and Determinants245× since 2002If the system of linear equations x−2y+z=−42x+αy+3z=53x−y+βz=3\begin{aligned} & x-2 y+z=-4 \\ & 2 x+\alpha y+3 z=5 \\ & 3 x-y+\beta z=3 \end{aligned}x−2y+z=−42x+αy+3z=53x−y+βz=3 has infinitely many solutions, then 12α+13β12 \alpha+13 \beta12α+13β is equal toAOption A. 60BOption B. 54COption C. 64DOption D. 58CheckSkip · show solution
