If the sum of the squares of the reciprocals of the roots α and β of the equation 3x² + λ x - 1 = 0 is 15, then 6(α ³ + β ³)² is equal to:

Complex Numbers and Quadratic Equations: JEE Main 2022 Mathematics question

JEE Main 2022 · 24 Jun, Morning shift · Q5155

JEE Main 202224 Jun, Morning shiftMathematicsHardComplex Numbers and Quadratic Equations264× since 2002

If the sum of the squares of the reciprocals of the roots

\alpha

and

\beta

of the equation 3x² +

\lambda

-

1 = 0 is 15, then 6(

\alpha

³ +

\beta

³)² is equal to :