JEE Main 20205 Sep, Evening shiftMathematicsEasySequence and Series179× since 2002If the sum of the first 20 terms of the series log(71/2)x+log(71/3)x+log(71/4)x+...{\log _{\left( {{7^{1/2}}} \right)}}x + {\log _{\left( {{7^{1/3}}} \right)}}x + {\log _{\left( {{7^{1/4}}} \right)}}x + ...log(71/2)x+log(71/3)x+log(71/4)x+... is 460, then x is equal to :AOption A. e²BOption B. 71/2COption C. 7²DOption D. 746/21CheckSkip · show solution
