JEE Main 2004Annual, Paper 1MathematicsMediumThree Dimensional Geometry249× since 2002If the straight lines x=1+s,y=−3x=1+s,y=-3x=1+s,y=−3−λs,- \lambda s,−λs, z=1+λsz = 1 + \lambda sz=1+λs and x=t2,y=1+t,z=2−t,x = {t \over 2},y = 1 + t,z = 2 - t,x=2t,y=1+t,z=2−t, with parameters sss and ttt respectively, are co-planar, then λ\lambdaλ equals :AOption A. 000BOption B. −1-1−1COption C. −12- {1 \over 2}−21DOption D. −2-2−2CheckSkip · show solution
