JEE Main 202427 Jan, Morning shiftMathematicsMediumDifferential Equations163× since 2002If the solution of the differential equation (2x+3y−2)dx+(4x+6y−7)dy=0,y(0)=3(2 x+3 y-2) \mathrm{d} x+(4 x+6 y-7) \mathrm{d} y=0, y(0)=3(2x+3y−2)dx+(4x+6y−7)dy=0,y(0)=3, is αx+βy+3loge∣2x+3y−γ∣=6\alpha x+\beta y+3 \log _e|2 x+3 y-\gamma|=6αx+βy+3loge∣2x+3y−γ∣=6, then α+2β+3γ\alpha+2 \beta+3 \gammaα+2β+3γ is equal to ____________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
