JEE Main 20244 Apr, Morning shiftMathematicsMediumDifferential Equations163× since 2002If the solution y=y(x)y=y(x)y=y(x) of the differential equation (x4+2x3+3x2+2x+2)dy−(2x2+2x+3)dx=0(x^4+2 x^3+3 x^2+2 x+2) \mathrm{d} y-(2 x^2+2 x+3) \mathrm{d} x=0(x4+2x3+3x2+2x+2)dy−(2x2+2x+3)dx=0 satisfies y(−1)=−π4y(-1)=-\frac{\pi}{4}y(−1)=−4π, then y(0)y(0)y(0) is equal to :AOption A. −π12-\frac{\pi}{12}−12πBOption B. π2\frac{\pi}{2}2πCOption C. 0DOption D. π4\frac{\pi}{4}4πCheckSkip · show solution
