If the shortest distance between the straight lines 3(x - 1) = 6(y - 2) = 2(z - 1) and 4(x - 2) = 2(y - λ) = (z - 3),λ R is 1/(√(38)), then the integral value of λ is equal to:

Three Dimensional Geometry: JEE Main 2021 Mathematics question

JEE Main 2021 · 22 Jul, Evening shift · Q2499

JEE Main 202122 Jul, Evening shiftMathematicsHardThree Dimensional Geometry249× since 2002

If the shortest distance between the straight lines

3(x - 1) = 6(y - 2) = 2(z - 1)

and

4(x - 2) = 2(y - \lambda ) = (z - 3),\lambda \in R

{1 \over {\sqrt {38} }}

, then the integral value of

\lambda

is equal to :

JEE Main 2021 · 22 Jul, Evening shift · Q2499

JEE Main 202122 Jul, Evening shiftMathematicsHardThree Dimensional Geometry249× since 2002

If the shortest distance between the straight lines

3(x - 1) = 6(y - 2) = 2(z - 1)

and

4(x - 2) = 2(y - \lambda ) = (z - 3),\lambda \in R

{1 \over {\sqrt {38} }}

, then the integral value of

\lambda

is equal to :