JEE Main 202427 Jan, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002If the shortest distance between the lines x−41=y+12=z−3\frac{x-4}{1}=\frac{y+1}{2}=\frac{z}{-3}1x−4=2y+1=−3z and x−λ2=y+14=z−2−5\frac{x-\lambda}{2}=\frac{y+1}{4}=\frac{z-2}{-5}2x−λ=4y+1=−5z−2 is 65\frac{6}{\sqrt{5}}56, then the sum of all possible values of λ\lambdaλ is :AOption A. 10BOption B. 5COption C. 7DOption D. 8CheckSkip · show solution
