JEE Main 20241 Feb, Morning shiftMathematicsHardThree Dimensional Geometry249× since 2002If the shortest distance between the lines x−λ−2=y−21=z−11\frac{x-\lambda}{-2}=\frac{y-2}{1}=\frac{z-1}{1}−2x−λ=1y−2=1z−1 and x−31=y−1−2=z−21\frac{x-\sqrt{3}}{1}=\frac{y-1}{-2}=\frac{z-2}{1}1x−3=−2y−1=1z−2 is 1 , then the sum of all possible values of λ\lambdaλ is :AOption A. 0BOption B. 232 \sqrt{3}23COption C. 333 \sqrt{3}33DOption D. −23-2 \sqrt{3}−23CheckSkip · show solution
