JEE Main 20238 Apr, Morning shiftMathematicsMediumVector Algebra184× since 2002If the points with position vectors αi^+10j^+13k^,6i^+11j^+11k^,92i^+βj^−8k^\alpha \hat{i}+10 \hat{j}+13 \hat{k}, 6 \hat{i}+11 \hat{j}+11 \hat{k}, \frac{9}{2} \hat{i}+\beta \hat{j}-8 \hat{k}αi^+10j^+13k^,6i^+11j^+11k^,29i^+βj^−8k^ are collinear, then (19α−6β)2(19 \alpha-6 \beta)^{2}(19α−6β)2 is equal to :AOption A. 16BOption B. 49COption C. 36DOption D. 25CheckSkip · show solution
