JEE Main 20205 Sep, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002
If the point P on the curve, 4x² + 5y² = 20 is
farthest from the point Q(0, -4), then PQ² is equal to:
JEE Main 2020 · 5 Sep, Morning shift · Q2649