JEE Main 2003Annual, Paper 1MathematicsEasyCoordinate Geometry478× since 2002If the pair of straight lines x2−2pxy−y2=0{x^2} - 2pxy - {y^2} = 0x2−2pxy−y2=0 and x2−2qxy−y2=0{x^2} - 2qxy - {y^2} = 0x2−2qxy−y2=0 be such that each pair bisects the angle between the other pair, then :AOption A. pq=−1pq = -1pq=−1BOption B. p=qp = qp=qCOption C. p=−qp = -qp=−qDOption D. pq=1pq = 1pq=1.CheckSkip · show solution