If the minimum value of f(x)=(5 x²)/2+(α)/(x⁵), x>0, is 14, then the value of α is equal to:

Limit, Continuity and Differentiability: JEE Main 2022 Mathematics question

JEE Main 2022 · 28 Jul, Morning shift · Q2671

JEE Main 202228 Jul, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

If the minimum value of

f(x)=\frac{5 x^{2}}{2}+\frac{\alpha}{x^{5}}, x>0

, is 14 , then the value of

\alpha

is equal to :

JEE Main 2022 · 28 Jul, Morning shift · Q2671

JEE Main 202228 Jul, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

If the minimum value of

f(x)=\frac{5 x^{2}}{2}+\frac{\alpha}{x^{5}}, x>0

, is 14 , then the value of

\alpha

is equal to :