JEE Main 202126 Feb, Evening shiftMathematicsMediumMatrices and Determinants245× since 2002If the matrix A=[10002030−1]A = \left[ {\matrix{ 1 & 0 & 0 \cr 0 & 2 & 0 \cr 3 & 0 & { - 1} \cr } } \right]A=10302000−1 satisfies the equation A20+αA19+βA=[100040001]{A^{20}} + \alpha {A^{19}} + \beta A = \left[ {\matrix{ 1 & 0 & 0 \cr 0 & 4 & 0 \cr 0 & 0 & 1 \cr } } \right]A20+αA19+βA=100040001 for some real numbers α\alphaα and β\betaβ, then β\betaβ −-− α\alphaα is equal to ___________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
