JEE Main 202127 Aug, Morning shiftMathematicsMediumMatrices and Determinants245× since 2002If the matrix A=(02K−1)A = \left( {\matrix{ 0 & 2 \cr K & { - 1} \cr } } \right)A=(0K2−1) satisfies A(A3+3I)=2IA({A^3} + 3I) = 2IA(A3+3I)=2I, then the value of K is :AOption A. 12{1 \over 2}21BOption B. −-−12{1 \over 2}21COption C. −-−1DOption D. 1CheckSkip · show solution
