JEE Main 202312 Apr, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002If the local maximum value of the function f(x)=(3e2sinx)sin2x,x∈(0,π2)f(x)=\left(\frac{\sqrt{3 e}}{2 \sin x}\right)^{\sin ^{2} x}, x \in\left(0, \frac{\pi}{2}\right)f(x)=(2sinx3e)sin2x,x∈(0,2π) , is ke\frac{k}{e}ek, then (ke)8+k8e5+k8\left(\frac{k}{e}\right)^{8}+\frac{k^{8}}{e^{5}}+k^{8}(ek)8+e5k8+k8 is equal toAOption A. e3+e6+e10e^{3}+e^{6}+e^{10}e3+e6+e10BOption B. e3+e5+e11e^{3}+e^{5}+e^{11}e3+e5+e11COption C. e3+e6+e11e^{3}+e^{6}+e^{11}e3+e6+e11DOption D. e5+e6+e11e^{5}+e^{6}+e^{11}e5+e6+e11CheckSkip · show solution