JEE Main 20199 Apr, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002If the line, x−12=y+13=z−24{{x - 1} \over 2} = {{y + 1} \over 3} = {{z - 2} \over 4}2x−1=3y+1=4z−2 meets the plane, x + 2y + 3z = 15 at a point P, then the distance of P from the origin is :AOption A. 52{{\sqrt 5 } \over 2}25BOption B. 25\sqrt 55COption C. 9/2DOption D. 7/2CheckSkip · show solution
