JEE Main 202622 Jan, Morning shiftMathematicsEasyCoordinate Geometry478× since 2002If the line αx+2y=1\alpha x+2y=1αx+2y=1, where α∈R\alpha\in\mathbb{R}α∈R, does not meet the hyperbola x2−9y2=9x^2-9y^2=9x2−9y2=9, then a possible value of α\alphaα is:AOption A. 0.80.80.8BOption B. 0.50.50.5COption C. 0.60.60.6DOption D. 0.70.70.7CheckSkip · show solution
