JEE Main 20245 Apr, Morning shiftMathematicsEasyThree Dimensional Geometry249× since 2002If the line 2−x3=3y−24λ+1=4−z\frac{2-x}{3}=\frac{3 y-2}{4 \lambda+1}=4-z32−x=4λ+13y−2=4−z makes a right angle with the line x+33μ=1−2y6=5−z7\frac{x+3}{3 \mu}=\frac{1-2 y}{6}=\frac{5-z}{7}3μx+3=61−2y=75−z, then 4λ+9μ4 \lambda+9 \mu4λ+9μ is equal to :AOption A. 4BOption B. 13COption C. 5DOption D. 6CheckSkip · show solution
