JEE Main 2012Annual, Paper 1MathematicsMediumIntegral Calculus369× since 2002If the ∫5tanxtanx−2dx=x+a ln ∣sinx−2cosx∣+k,\int {{{5\tan x} \over {\tan x - 2}}dx = x + a\,\ln \,\left| {\sin x - 2\cos x} \right| + k,}∫tanx−25tanxdx=x+aln∣sinx−2cosx∣+k, then aaa is equal to :AOption A. −1-1−1BOption B. −2-2−2COption C. 111DOption D. 222CheckSkip · show solution
