JEE Main 2015Session, Shift 1MathematicsMediumLimit, Continuity and Differentiability420× since 2002If the function. g(x)={kx+1,0≤x≤3m x+2,3<x≤5g\left( x \right) = \left\{ {\matrix{ {k\sqrt {x + 1} ,} & {0 \le x \le 3} \cr {m\,x + 2,} & {3 < x \le 5} \cr } } \right.g(x)={kx+1,mx+2,0≤x≤33<x≤5 is differentiable, then the value of k+mk+mk+m is :AOption A. 103{{10} \over 3}310BOption B. 444COption C. 222DOption D. 165{{16} \over 5}516CheckSkip · show solution