JEE Main 20169 Apr, Morning shiftMathematicsHardLimit, Continuity and Differentiability420× since 2002If the function f(x) = {−xx<1a+cos−1(x+b),1≤x≤2\left\{ {\matrix{ { - x} & {x < 1} \cr {a + {{\cos }^{ - 1}}\left( {x + b} \right),} & {1 \le x \le 2} \cr } } \right.{−xa+cos−1(x+b),x<11≤x≤2 is differentiable at x = 1, then ab{a \over b}ba is equal to :AOption A. π−22{{\pi - 2} \over 2}2π−2BOption B. −π−22{{ - \pi - 2} \over 2}2−π−2COption C. π+22{{\pi + 2} \over 2}2π+2DOption D. −1−cos−1(2)- 1 - {\cos ^{ - 1}}\left( 2 \right)−1−cos−1(2)CheckSkip · show solution
