JEE Main 20199 Apr, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002If the function f(x)={a∣π−x∣+1,x≤5b∣x−π∣+3,x>5f(x) = \left\{ {\matrix{ {a|\pi - x| + 1,x \le 5} \cr {b|x - \pi | + 3,x > 5} \cr } } \right.f(x)={a∣π−x∣+1,x≤5b∣x−π∣+3,x>5 is continuous at x = 5, then the value of a – b is :-AOption A. 2π−5{2 \over {\pi - 5 }}π−52BOption B. 25−π{2 \over {5 - \pi }}5−π2COption C. −2π+5{-2 \over {\pi + 5 }}π+5−2DOption D. 2π+5{2 \over {\pi + 5 }}π+52CheckSkip · show solution
