JEE Main 202430 Jan, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002If the function f(x)={1∣x∣,∣x∣⩾2ax2+2 b,∣x∣<2f(x)= \begin{cases}\frac{1}{|x|}, & |x| \geqslant 2 \\ \mathrm{a} x^2+2 \mathrm{~b}, & |x|<2\end{cases}f(x)={∣x∣1,ax2+2 b,∣x∣⩾2∣x∣<2 is differentiable on R\mathbf{R}R, then 48(a+b)48(a+b)48(a+b) is equal to __________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
