If the function f(x) = \ k₁(x - π)² - 1, x ≤ π k₂ cos x, x > π. is twice differentiable, then the ordered pair (k₁, k₂) is equal to:

Limit, Continuity and Differentiability: JEE Main 2020 Mathematics question

JEE Main 2020 · 5 Sep, Morning shift · Q4196

JEE Main 20205 Sep, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

If the function

f\left( x \right) = \left\{ {\matrix{ {{k_1}{{\left( {x - \pi } \right)}^2} - 1,} & {x \le \pi } \cr {{k_2}\cos x,} & {x > \pi } \cr } } \right.

is twice differentiable, then the ordered pair (k₁, k₂) is equal to :

JEE Main 2020 · 5 Sep, Morning shift · Q4196

JEE Main 20205 Sep, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

If the function

f\left( x \right) = \left\{ {\matrix{ {{k_1}{{\left( {x - \pi } \right)}^2} - 1,} & {x \le \pi } \cr {{k_2}\cos x,} & {x > \pi } \cr } } \right.

is twice differentiable, then the ordered pair (k₁, k₂) is equal to :