If the function ƒ defined on (- 1/3,1/3) by f(x) = \ 1/x log e ((1 + 3x)/(1 - 2x)), when x ≠ 0 k, when x = 0. is continuous, then k is equal to _ _ _ _.

Limit, Continuity and Differentiability: JEE Main 2020 Mathematics question

JEE Main 2020 · 7 Jan, Evening shift · Q31

JEE Main 20207 Jan, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

If the function ƒ defined on

\left( { - {1 \over 3},{1 \over 3}} \right)

by f(x) =

\left\{ {\matrix{ {{1 \over x}{{\log }_e}\left( {{{1 + 3x} \over {1 - 2x}}} \right),} & {when\,x \ne 0} \cr {k,} & {when\,x = 0} \cr } } \right.

is continuous, then k is equal to_______.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2020 · 7 Jan, Evening shift · Q31

JEE Main 20207 Jan, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

If the function ƒ defined on

\left( { - {1 \over 3},{1 \over 3}} \right)

by f(x) =

\left\{ {\matrix{ {{1 \over x}{{\log }_e}\left( {{{1 + 3x} \over {1 - 2x}}} \right),} & {when\,x \ne 0} \cr {k,} & {when\,x = 0} \cr } } \right.

is continuous, then k is equal to_______.

Your answerType your answer. Integers and decimals are accepted.