JEE Main 202325 Jan, Evening shiftMathematicsMediumVector Algebra184× since 2002If the four points, whose position vectors are 3i^−4j^+2k^,i^+2j^−k^,−2i^−j^+3k^3\widehat i - 4\widehat j + 2\widehat k,\widehat i + 2\widehat j - \widehat k, - 2\widehat i - \widehat j + 3\widehat k3i−4j+2k,i+2j−k,−2i−j+3k and 5i^−2αj^+4k^5\widehat i - 2\alpha \widehat j + 4\widehat k5i−2αj+4k are coplanar, then α\alphaα is equal to :AOption A. 7317{{73} \over {17}}1773BOption B. −7317- {{73} \over {17}}−1773COption C. −10717- {{107} \over {17}}−17107DOption D. 10717{{107} \over {17}}17107CheckSkip · show solution
