If the foot of the perpendicular from point (4, 3, 8) on the line L₁:(x - a)/l = (y - 2)/3 = (z - b)/4, l ≠ 0 is (3, 5, 7), then the shortest distance between the line L₁ and line L₂:(x - 2)/3 = (y - 4)/4 = (z - 5)/5 is equal to:

Three Dimensional Geometry: JEE Main 2021 Mathematics question

JEE Main 2021 · 16 Mar, Evening shift · Q2497

JEE Main 202116 Mar, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002

If the foot of the perpendicular from point (4, 3, 8) on the line

{L_1}:{{x - a} \over l} = {{y - 2} \over 3} = {{z - b} \over 4}

, l

\ne

0 is (3, 5, 7), then the shortest distance between the line L₁ and line

{L_2}:{{x - 2} \over 3} = {{y - 4} \over 4} = {{z - 5} \over 5}

is equal to :

JEE Main 2021 · 16 Mar, Evening shift · Q2497

JEE Main 202116 Mar, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002

If the foot of the perpendicular from point (4, 3, 8) on the line

{L_1}:{{x - a} \over l} = {{y - 2} \over 3} = {{z - b} \over 4}

, l

\ne

0 is (3, 5, 7), then the shortest distance between the line L₁ and line

{L_2}:{{x - 2} \over 3} = {{y - 4} \over 4} = {{z - 5} \over 5}

is equal to :