JEE Main 2006Annual, Paper 1MathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002If the expansion in powers of xxx of the function 1(1−ax)(1−bx){1 \over {\left( {1 - ax} \right)\left( {1 - bx} \right)}}(1−ax)(1−bx)1 is a0+a1x+a2x2+a3x3.....{a_0} + {a_1}x + {a_2}{x^2} + {a_3}{x^3}.....a0+a1x+a2x2+a3x3..... then an{a_n}an isAOption A. bn−anb−a{{{b^n} - {a^n}} \over {b - a}}b−abn−anBOption B. an−bnb−a{{{a^n} - {b^n}} \over {b - a}}b−aan−bnCOption C. an+1−bn+1b−a{{{a^{n + 1}} - {b^{n + 1}}} \over {b - a}}b−aan+1−bn+1DOption D. bn+1−an+1b−a{{{b^{n + 1}} - {a^{n + 1}}} \over {b - a}}b−abn+1−an+1CheckSkip · show solution