JEE Main 202227 Jun, Evening shiftMathematicsMediumCoordinate Geometry478× since 2002If the equation of the parabola, whose vertex is at (5, 4) and the directrix is 3x+y−29=03x + y - 29 = 03x+y−29=0, is x2+ay2+bxy+cx+dy+k=0{x^2} + a{y^2} + bxy + cx + dy + k = 0x2+ay2+bxy+cx+dy+k=0, then a+b+c+d+ka + b + c + d + ka+b+c+d+k is equal to :AOption A. 575BOption B. −-−575COption C. 576DOption D. −-−576CheckSkip · show solution
