JEE Main 2007Annual, Paper 1MathematicsMediumComplex Numbers and Quadratic Equations264× since 2002If the difference between the roots of the equation x2+ax+1=0{x^2} + ax + 1 = 0x2+ax+1=0 is less than 5,\sqrt 5 ,5, then the set of possible values of aaa isAOption A. (3,∞)\left( {3,\infty } \right)(3,∞)BOption B. (−∞,−3)\left( { - \infty , - 3} \right)(−∞,−3)COption C. (−3,3)\left( { - 3,3} \right)(−3,3)DOption D. (−3,∞)\left( { - 3,\infty } \right)(−3,∞)CheckSkip · show solution
