If the curve y = y(x) is the solution of the differential equation 2(x² + x^(5/4))dy - y(x + x^(1/4))dx = 2x^(9/4)dx, x > 0 which passes through the point (1,1 - 4/3 log e 2), then the value of y(16) is equal to:

Differential Equations: JEE Main 2021 Mathematics question

JEE Main 2021 · 17 Mar, Evening shift · Q3529

JEE Main 202117 Mar, Evening shiftMathematicsMediumDifferential Equations163× since 2002

If the curve y = y(x) is the solution of the differential equation

2({x^2} + {x^{5/4}})dy - y(x + {x^{1/4}})dx = {2x^{9/4}}dx

, x > 0 which passes through the point

\left( {1,1 - {4 \over 3}{{\log }_e}2} \right)

, then the value of y(16) is equal to :

JEE Main 2021 · 17 Mar, Evening shift · Q3529

JEE Main 202117 Mar, Evening shiftMathematicsMediumDifferential Equations163× since 2002

If the curve y = y(x) is the solution of the differential equation

2({x^2} + {x^{5/4}})dy - y(x + {x^{1/4}})dx = {2x^{9/4}}dx

, x > 0 which passes through the point

\left( {1,1 - {4 \over 3}{{\log }_e}2} \right)

, then the value of y(16) is equal to :