If the constant term in the expansion of (3x³ - 2x² + 5/(x⁵))¹⁰ is 2^(k).l, where l is an odd integer, then the value of k is equal to:

Binomial Theorem and Its Simple Applications: JEE Main 2022 Mathematics question

JEE Main 2022 · 29 Jun, Morning shift · Q2957

JEE Main 202229 Jun, Morning shiftMathematicsHardBinomial Theorem and Its Simple Applications131× since 2002

If the constant term in the expansion of

{\left( {3{x^3} - 2{x^2} + {5 \over {{x^5}}}} \right)^{10}}

is 2^k.l, where l is an odd integer, then the value of k is equal to:

JEE Main 2022 · 29 Jun, Morning shift · Q2957

JEE Main 202229 Jun, Morning shiftMathematicsHardBinomial Theorem and Its Simple Applications131× since 2002

If the constant term in the expansion of

{\left( {3{x^3} - 2{x^2} + {5 \over {{x^5}}}} \right)^{10}}

is 2^k.l, where l is an odd integer, then the value of k is equal to: