If the coefficients of x⁷ in (x² + 1/bx)¹¹ and x⁻⁷ in (x - 1/(bx²))¹¹, b ≠ 0, are equal, then the value of b is equal to:

Binomial Theorem and Its Simple Applications: JEE Main 2021 Mathematics question

JEE Main 2021 · 27 Jul, Morning shift · Q2935

JEE Main 202127 Jul, Morning shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002

If the coefficients of x⁷ in

{\left( {{x^2} + {1 \over {bx}}} \right)^{11}}

and x^

-

7 in

{\left( {{x} - {1 \over {bx^2}}} \right)^{11}}

, b

\ne

0, are equal, then the value of b is equal to :