JEE Main 20236 Apr, Evening shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002If the coefficient of x7{x^7}x7 in (ax2+12bx)11{\left( {a{x^2} + {1 \over {2bx}}} \right)^{11}}(ax2+2bx1)11 and x−7{x^{ - 7}}x−7 in (ax−13bx2)11{\left( {ax - {1 \over {3b{x^2}}}} \right)^{11}}(ax−3bx21)11 are equal, then :AOption A. 243ab=64243ab = 64243ab=64BOption B. 32ab=72932ab = 72932ab=729COption C. 64ab=24364ab = 24364ab=243DOption D. 729ab=32729ab = 32729ab=32CheckSkip · show solution