JEE Main 20246 Apr, Evening shiftMathematicsMediumIntegral Calculus369× since 2002If the area of the region {(x,y):ax2≤y≤1x,1≤x≤2,0<a<1}\left\{(x, y): \frac{\mathrm{a}}{x^2} \leq y \leq \frac{1}{x}, 1 \leq x \leq 2,0<\mathrm{a}<1\right\}{(x,y):x2a≤y≤x1,1≤x≤2,0<a<1} is (loge2)−17\left(\log _{\mathrm{e}} 2\right)-\frac{1}{7}(loge2)−71 then the value of 7a−37 \mathrm{a}-37a−3 is equal to :AOption A. 1BOption B. 0COption C. 2DOption D. −-−1CheckSkip · show solution
