JEE Main 202127 Jul, Morning shiftMathematicsMediumIntegral Calculus369× since 2002If the area of the bounded region R={(x,y):max{0,logex}≤y≤2x,12≤x≤2}R = \left\{ {(x,y):\max \{ 0,{{\log }_e}x\} \le y \le {2^x},{1 \over 2} \le x \le 2} \right\}R={(x,y):max{0,logex}≤y≤2x,21≤x≤2} is , α(loge2)−1+β(loge2)+γ\alpha {({\log _e}2)^{ - 1}} + \beta ({\log _e}2) + \gammaα(loge2)−1+β(loge2)+γ, then the value of (α+β−2λ)2{(\alpha + \beta - 2\lambda )^2}(α+β−2λ)2 is equal to :AOption A. 8BOption B. 2COption C. 4DOption D. 1CheckSkip · show solution
