JEE Main 201912 Apr, Morning shiftMathematicsMediumIntegral Calculus369× since 2002If the area (in sq. units) of the region {(x, y) : y² ≤\le≤ 4x, x + y ≤\le≤ 1, x ≥\ge≥ 0, y ≥\ge≥ 0} is a 2\sqrt 22 + b, then a – b is equal to :AOption A. 83{8 \over 3}38BOption B. −23- {2 \over 3}−32COption C. 6DOption D. 103{{10} \over 3}310CheckSkip · show solution
