JEE Main 201910 Jan, Morning shiftMathematicsEasyIntegral Calculus369× since 2002If the area enclosed between the curves y = kx² and x = ky², (k > 0), is 1 square unit. Then k is -AOption A. 3\sqrt 33BOption B. 32{{\sqrt 3 } \over 2}23COption C. 23{2 \over {\sqrt 3 }}32DOption D. 13{1 \over {\sqrt 3 }}31CheckSkip · show solution
