If the angle between the lines, x/2 = y/2 = z/1 and (5 - x)/(- 2) = (7y - 14)/p = (z - 3)/4 is cos ⁻¹(2/3), then p is equal to:

Three Dimensional Geometry: JEE Main 2018 Mathematics question

JEE Main 2018 · 16 Apr, Morning shift · Q2487

JEE Main 201816 Apr, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002

If the angle between the lines,

{x \over 2} = {y \over 2} = {z \over 1}

and

{{5 - x} \over { - 2}} = {{7y - 14} \over p} = {{z - 3} \over 4}\,\,

{\cos ^{ - 1}}\left( {{2 \over 3}} \right),

then p is equal to :

JEE Main 2018 · 16 Apr, Morning shift · Q2487

JEE Main 201816 Apr, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002

If the angle between the lines,

{x \over 2} = {y \over 2} = {z \over 1}

and

{{5 - x} \over { - 2}} = {{7y - 14} \over p} = {{z - 3} \over 4}\,\,

{\cos ^{ - 1}}\left( {{2 \over 3}} \right),

then p is equal to :