JEE Main 202225 Jul, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002If the absolute maximum value of the function f(x)=(x2−2x+7)e(4x3−12x2−180x+31)f(x)=\left(x^{2}-2 x+7\right) \mathrm{e}^{\left(4 x^{3}-12 x^{2}-180 x+31\right)}f(x)=(x2−2x+7)e(4x3−12x2−180x+31) in the interval [−3,0][-3,0][−3,0] is f(α)f(\alpha)f(α), then :AOption A. α=0\alpha=0α=0BOption B. α=−3\alpha=-3α=−3COption C. α∈(−1,0)\alpha \in(-1,0)α∈(−1,0)DOption D. α∈(−3,−1]\alpha \in(-3,-1]α∈(−3,−1]CheckSkip · show solution
