JEE Main 202330 Jan, Morning shiftMathematicsEasyIntegral Calculus369× since 2002If [t] denotes the greatest integer ≤t\le \mathrm{t}≤t, then the value of 3(e−1)e∫12x2e[x]+[x3]dx{{3(e - 1)} \over e}\int\limits_1^2 {{x^2}{e^{[x] + [{x^3}]}}dx}e3(e−1)1∫2x2e[x]+[x3]dx is :AOption A. e8−e\mathrm{e^8-e}e8−eBOption B. e7−1\mathrm{e^7-1}e7−1COption C. e9−e\mathrm{e^9-e}e9−eDOption D. e8−1\mathrm{e^8-1}e8−1CheckSkip · show solution
