JEE Main 202628 Jan, Evening shiftMathematicsMediumSequence and Series179× since 2002If ∑r=125(rr4+r2+1)=pq\sum_{r=1}^{25} \left(\frac{r}{r^4 + r^2 + 1}\right) = \frac{p}{q}∑r=125(r4+r2+1r)=qp, where p and q are positive integers such that gcd(p,q)=1\gcd(p, q) = 1gcd(p,q)=1, then p+qp + qp+q is equal to ________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
