JEE Main 201910 Jan, Evening shiftMathematicsMediumPermutations and Combinations98× since 2002If ∑r=025{50Cr.50−rC25−r}=K(50C25), \sum\limits_{r = 0}^{25} {\left\{ {{}^{50}{C_r}.{}^{50 - r}{C_{25 - r}}} \right\} = K\left( {^{50}{C_{25}}} \right)} ,\,\,r=0∑25{50Cr.50−rC25−r}=K(50C25), then K is equal to :AOption A. 2²⁴BOption B. 2²⁵−-− 1COption C. 2²⁵DOption D. (25)²CheckSkip · show solution
