JEE Main 202226 Jul, Evening shiftMathematicsMediumSequence and Series179× since 2002If ∑k=110kk4+k2+1=mn\sum\limits_{k=1}^{10} \frac{k}{k^{4}+k^{2}+1}=\frac{m}{n}k=1∑10k4+k2+1k=nm, where m and n are co-prime, then m+nm+nm+n is equal to _____________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
