JEE Main 2018Session, Shift 1MathematicsMediumStatistics and Probability258× since 2002If ∑i=19(xi−5)=9\sum\limits_{i = 1}^9 {\left( {{x_i} - 5} \right)} = 9i=1∑9(xi−5)=9 and ∑i=19(xi−5)2=45\sum\limits_{i = 1}^9 {{{\left( {{x_i} - 5} \right)}^2}} = 45i=1∑9(xi−5)2=45, then the standard deviation of the 9 items x1,x2,.......,x9{x_1},{x_2},.......,{x_9}x1,x2,.......,x9 isAOption A. 3BOption B. 9COption C. 4DOption D. 2CheckSkip · show solution
