JEE Main 202125 Feb, Morning shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002If Rolle's theorem holds for the function f(x)=x3−ax2+bx−4f(x) = {x^3} - a{x^2} + bx - 4f(x)=x3−ax2+bx−4, x∈[1,2]x \in [1,2]x∈[1,2] with f′(43)=0f'\left( {{4 \over 3}} \right) = 0f′(34)=0, then ordered pair (a, b) is equal to :AOption A. (−-−5, −-−8)BOption B. (5, −-−8)COption C. (−-−5, 8)DOption D. (5, 8)CheckSkip · show solution
