JEE Main 202131 Aug, Evening shiftPhysicsEasyGravitation159× since 2002If R_E be the radius of Earth, then the ratio between the acceleration due to gravity at a depth 'r' below and a height 'r' above the earth surface is : (Given : r < R_E)AOption A. 1−rRE−r2RE2−r3RE31 - {r \over {{R_E}}} - {{{r^2}} \over {R_E^2}} - {{{r^3}} \over {R_E^3}}1−REr−RE2r2−RE3r3BOption B. 1+rRE+r2RE2+r3RE31 + {r \over {{R_E}}} + {{{r^2}} \over {R_E^2}} + {{{r^3}} \over {R_E^3}}1+REr+RE2r2+RE3r3COption C. 1+rRE−r2RE2+r3RE31 + {r \over {{R_E}}} - {{{r^2}} \over {R_E^2}} + {{{r^3}} \over {R_E^3}}1+REr−RE2r2+RE3r3DOption D. 1+rRE−r2RE2−r3RE31 + {r \over {{R_E}}} - {{{r^2}} \over {R_E^2}} - {{{r^3}} \over {R_E^3}}1+REr−RE2r2−RE3r3CheckSkip · show solution
