JEE Main 202325 Jan, Morning shiftPhysicsHardKinematics177× since 2002If P→=3i^+3j^+2k^\overrightarrow P = 3\widehat i + \sqrt 3 \widehat j + 2\widehat kP=3i+3j+2k and Q→=4i^+3j^+2.5k^\overrightarrow Q = 4\widehat i + \sqrt 3 \widehat j + 2.5\widehat kQ=4i+3j+2.5k then, the unit vector in the direction of P→×Q→\overrightarrow P \times \overrightarrow QP×Q is 1x(3i^+j^−23k^){1 \over x}\left( {\sqrt 3 \widehat i + \widehat j - 2\sqrt 3 \widehat k} \right)x1(3i+j−23k). The value of xxx is _________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution